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4w^2-100w+400=0
a = 4; b = -100; c = +400;
Δ = b2-4ac
Δ = -1002-4·4·400
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-60}{2*4}=\frac{40}{8} =5 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+60}{2*4}=\frac{160}{8} =20 $
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